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The boiling point elevation constant for toluene is 3.32 K $kg mol^{-1}$, the normal boiling point of toluene is 110.7$^{\large\circ}$C. The enthalpy of vaporization of toluene would by nearly:

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34.0 kJ $mol^{-1 }$
Hence (B) is the correct answer.
answered Jun 17, 2014 by sreemathi.v

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