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The capacitance of a parallel plate capacitor is $5 \mu F$. When a glass slab of thickness equal to the separation between the plates is introduced between the plates, the potential difference reduces to $\large\frac{1}{8}$ of the original value. The dielectric constant of glass is

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(C) 8
Hence C is the correct answer.
answered Jun 17, 2014 by meena.p

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