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The molal boiling point constant of water is 0.573$^{\large\circ}C Kg mole^{–1}$. When 0.1 mole of glucose is dissolved in 1000 gm of water, the solution boils under atmospheric pressure at

1 Answer

$100 . 0573^{\large\circ}$C
Hence (B) is the correct answer.
answered Jun 17, 2014 by sreemathi.v

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