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Five identical capacitors, when connected in series, produce equivalent capacitance of $6 \mu F$. Now these capacitors are rearranged so as to produce the maximum value of equivalent capacitance. Find the maximum value of capacity that can be obtained.

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Let C be the capacitance of each capacitor.
Then $6= \large\frac{C}{5}$
$=> C= 3 \mu F$
If these are connected in parallel, then equivalent capacitance will be maximum.
$C'=30 \times 5$
$\qquad= 150 \mu F$
Hence A is the correct answer.
answered Jun 17, 2014 by meena.p
 

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