# Five identical capacitors, when connected in series, produce equivalent capacitance of $6 \mu F$. Now these capacitors are rearranged so as to produce the maximum value of equivalent capacitance. Find the maximum value of capacity that can be obtained.

Then $6= \large\frac{C}{5}$
$=> C= 3 \mu F$
$C'=30 \times 5$
$\qquad= 150 \mu F$