Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Five identical capacitors, when connected in series, produce equivalent capacitance of $6 \mu F$. Now these capacitors are rearranged so as to produce the maximum value of equivalent capacitance. Find the maximum value of capacity that can be obtained.

Can you answer this question?

1 Answer

0 votes
Let C be the capacitance of each capacitor.
Then $6= \large\frac{C}{5}$
$=> C= 3 \mu F$
If these are connected in parallel, then equivalent capacitance will be maximum.
$C'=30 \times 5$
$\qquad= 150 \mu F$
Hence A is the correct answer.
answered Jun 17, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App