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# Find the equivalent capacitance of the combination shown in figure between the points P and N.

The $10 \mu F$ and $20 \mu F$ capacitors are connected in parallel.
Their equivalent capacitance is $10 \mu F + 20 \mu F = 30 \mu F$.
We can replace the $10 \mu F$ and $20 \mu F$ the capacitors by a single capacitor of capacitance $30 \mu F$ between P and Q.
This is connected in series with the given $30 \mu F$ capacitor.
$\large\frac{1}{C} =\frac{1}{30 \mu F}+\frac{1}{30 \mu F}$
$C= 15 \mu F$