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When 250 mg of eugenol is added to 100 gm of camphor ($K_f $= 39.7), it lowered the freezing point by 0.62$^{\large\circ}$C. The molar mass of eugenol is

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$1.6 \times 10^2$ gm/mole
Hence (A) is the correct answer.
answered Jun 18, 2014 by sreemathi.v

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