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The molal lowering of vapour pressure of a liquid is 1.008 mm of Hg at $25^{\large\circ}$C in a very dilute solution containing non volatile solute. The vapour pressure of liquid at 25$^{\large\circ}$C is x 10 mm of Hg. The value of x is [molecular weight of liquid = 18]

1 Answer

6
Hence (A) is the correct answer.
answered Jun 18, 2014 by sreemathi.v
 

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