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The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs of identical size as shown in figure. If the dielectric constants of the three slabs are $K_1, K_2$ and $K_3$, find the new capacitance.

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$C_{eq}=(K_1+K_2+K_3)\large\frac{C}{3}$
answered Jun 18, 2014 by meena.p
 

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