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Three particles of a solute ‘A’ associate in benzene to form species (A)3. Calculate the freezing point of 0.25 molal solution. The degree of association of solute 'A' is found to be 0.80. The freezing point of benzene is 5.50C and its cryosopic constant is 5.12 $K m^{-1}.$

1 Answer

Hence (D) is the correct answer.
answered Jun 19, 2014 by sreemathi.v

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