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The Henry’s law constant for the solubility of $N_2$ gas in water at 298 K is $1.0 \times 10^5$ atm. The mole fraction of $N_2$ in air is 0.8. The number of moles of $N_2$ from air dissolved in 10 moles of water of 298 K and 5 atm pressure is

1 Answer

$4 \times 10^{−4}$
Hence (A) is the correct answer.
answered Jun 19, 2014 by sreemathi.v
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