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On mixing heptanes and octane from an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptanes and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptanes and 35 g of octane will be (molar mass of heptanes = 100 g $mol^{−1}$).

1 Answer

Hence (A) is the correct answer.
answered Jun 19, 2014 by sreemathi.v