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The freezing point (in $^{\large\circ}C$) of solution containing of 0.1 g of $K_3 [Fe(CN)_6]$ (mol. wt. 329) in 100 g of water ($K_f = 1.86 K kg mol^{−1}$) is

1 Answer

$-2.3\times 10^{-2}$
Hence (A) is the correct answer.
answered Jun 19, 2014 by sreemathi.v
 
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