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The degree of dissociation ($\alpha$) of a weak electrolyte, $A_xB_y$ is related to van’t Hoff factor (i) by the expression

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1 Answer

$\alpha=\large\frac{i-1}{(x+y-1)}$
Hence (A) is the correct answer.
answered Jun 19, 2014 by sreemathi.v
 
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