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A $600\; pF$ capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged $600\; pF$ capacitor. How much electrostatic energy is lost in the process?

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Charge on capacitor q = CV
$\qquad= (600 \times 10^{-12} )(200 ) =12 \times 10^{-8}$ coulomb
when capacitor is connected to the same uncharged capacitor then charge will be equally distributed.
answered Jun 19, 2014 by meena.p
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