$\begin{array}{1 1}(A)\;66\\(B)\;156\\(C)\;60\\(D)\;\text{None of these}\end{array} $

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- $C(n,r)=\large\frac{n!}{r!(n-r)!}$

In a committee of 5 persons the gentlemen will be in majority if the number of gentlemen $\geq 3$

Total number of ways of forming committee=$4C_3\times 6C_2+4C_4\times 6C_1$

$\Rightarrow 4\times 15+1\times 6$

$\Rightarrow 60+6$

$\Rightarrow 66$

Hence (A) is the correct answer.

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