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Determine the order and degree of following differential equation $ \bigg(\large \frac{ds}{dt} \bigg)^4 +$$ 3s\bigg(\large \frac{d^2s}{dt^2} \bigg) $$= 0 $
cbse
class12
modelpaper
2012
sec-a
q7
easy
math
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asked
Feb 7, 2013
by
thanvigandhi_1
edited
Nov 6, 2013
by
sreemathi.v
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The highest order derivative present in the differential equation determines its order.The highest power raise to the derivative determines its degree.
Given equation is $\bigg(\large\frac{ds}{dt}\bigg)^4$$+3s\big(\large\frac{d^2s}{dt^2}\big)$$=0$
In this equation the highest order is two and degree to which it is raised is 1
Hence the order is two and degree is one.
answered
Nov 6, 2013
by
sreemathi.v
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