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# The number of ways to give away 20 apples to 3 boys,each boy receiving atleast 4 apples is

$\begin{array}{1 1}(A)\;10C_8\\(B)\;90\\(C)\;22C_{20}\\(D)\;\text{None of these}\end{array}$

$\therefore$ The required number of ways =the number of non-negative integral solutions of $(x+y+z=8)$
$\Rightarrow 10C_8$