Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

The number of ways to give away 20 apples to 3 boys,each boy receiving atleast 4 apples is

$\begin{array}{1 1}(A)\;10C_8\\(B)\;90\\(C)\;22C_{20}\\(D)\;\text{None of these}\end{array} $

Can you answer this question?

1 Answer

0 votes
After giving away 4 apples to each boy,8 apples are left to be distributed among 3 boys.
$\therefore$ The required number of ways =the number of non-negative integral solutions of $(x+y+z=8)$
$\Rightarrow 10C_8$
Hence (A) is the correct answer.
answered Jun 20, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App