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The number of ways to give away 20 apples to 3 boys,each boy receiving atleast 4 apples is

$\begin{array}{1 1}(A)\;10C_8\\(B)\;90\\(C)\;22C_{20}\\(D)\;\text{None of these}\end{array} $

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After giving away 4 apples to each boy,8 apples are left to be distributed among 3 boys.
$\therefore$ The required number of ways =the number of non-negative integral solutions of $(x+y+z=8)$
$\Rightarrow 10C_8$
Hence (A) is the correct answer.
answered Jun 20, 2014 by sreemathi.v

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