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Permutations and Combinations
The number of ways to give away 20 apples to 3 boys,each boy receiving atleast 4 apples is
$\begin{array}{1 1}(A)\;10C_8\\(B)\;90\\(C)\;22C_{20}\\(D)\;\text{None of these}\end{array} $
cbse
math
class11
ch7
permutations-and-combinations
additionalproblem
q29
sec-a
easy
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Jun 20, 2014
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1 Answer
After giving away 4 apples to each boy,8 apples are left to be distributed among 3 boys.
$\therefore$ The required number of ways =the number of non-negative integral solutions of $(x+y+z=8)$
$\Rightarrow 10C_8$
Hence (A) is the correct answer.
answered
Jun 20, 2014
by
sreemathi.v
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