Total number of words starting with C=5!=120
Which include the word COCHIN also.
$\therefore$ The number of words that appear before the word COCHIN is less than 120.
Now total no. of words starting with CC=$4!=24$
Similarly in each of the cases total word starting with CH,CI,CN is 4!=24
$\therefore$ Total no. of words before starting with 10=$4\times 24=9!$
The first word with CO in alphabetical order is COCHIN.
Hence (C) is the correct answer.