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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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At an electron,a voter may vote for any number of candidates not greater than the number to be elected.There are 10 candidates and 4 are to be elected.If a voter votes for atleast for atleast one candidate,then the number of ways in which he can vote is

$\begin{array}{1 1}(A)\;6210\\(B)\;385\\(C)\;1110\\(D)\;5040\end{array} $

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1 Answer

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Total number of ways :-
$\Rightarrow 10C_1+10C_2+10C_3+10C_4$
$\Rightarrow 10+45+120+210$
$\Rightarrow 385$
Hence (B) is the correct answer.
answered Jun 20, 2014 by sreemathi.v
 

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