Browse Questions

# The number of ways four boys can be seated around a round-table in four chairs of different colours is

$\begin{array}{1 1}(A)\;24\\(B)\;12\\(C)\;23\\(D)\;64\end{array}$

Toolbox:
• $n!=n(n-1)(n-2)(n-3).....(3)(2)(1)$
Total no of boys =4
Total no of chairs =4
Required number of ways =4!
$\Rightarrow 4\times 3\times 2\times 1$
$\Rightarrow 24$
Hence (A) is the correct answer.