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How many numbers of 6 digits can be formed from the digits of the number 112233?

$\begin{array}{1 1}(A)\;30\\(B)\;60\\(C)\;90\\(D)\;120\end{array} $

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  • $n!=n(n-1)(n-2)(n-3).......(3)(2)(1)$
Total no. of digits =6
Total no. =112233
From 112233,the number of 6 digit that can be formed are
$\Rightarrow \large\frac{6!}{2!2!2!}$
$\Rightarrow \large\frac{6\times 5\times 4\times 3\times 2\times 1}{2\times 2 \times 2}$
$\Rightarrow 90$
Hence (C) is the correct answer.
answered Jun 20, 2014 by sreemathi.v

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