Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

In how many number of ways can 10 students be divided into three teams,one containing four students and the other three?

$\begin{array}{1 1}(A)\;400\\(B)\;700\\(C)\;1050\\(D)\;2100\end{array} $

Can you answer this question?

1 Answer

0 votes
  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
Total no. of students =10
Total no. of teams =3
Required no. of ways =$\large\frac{10C_4\times 6C_3\times 3C_3}{2!}$
$\Rightarrow \large\frac{10\times 9\times 8\times 7\times 6!}{4\times 3\times 2\times 6!}$$=210$
$\Rightarrow \large\frac{6\times 5\times 4\times 3!}{3!0!}$$=1$
$\Rightarrow \large\frac{210\times 20\times 1}{2}$
$\Rightarrow 2100$
Hence (D) is the correct answer.
answered Jun 20, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App