Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

The number of selecting atleast 4 candidates from 8 candidates is

$\begin{array}{1 1}(A)\;270\\(B)\;70\\(C)\;163\\(D)\;\text{None of these}\end{array} $

Can you answer this question?

1 Answer

0 votes
  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
Total candidates =8
Selection of the candidates =4
Required no. of selections =$8C_4+8C_5+8C_6+8C_7+8C_8$
$\Rightarrow 70+56+28+8+1$
$\Rightarrow 163$
Hence (C) is the correct answer.
answered Jun 20, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App