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A capacitor of $200 pF$ is charged by a $300\; V$ battery. The battery is then disconnected and the charge capacitor is connected to another uncharged capacitor of $100\; pF$. Calculate the difference between the final energy stored in the combined system and the initial energy stored in the single capacitor.

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$(D)\;3 \times 10^{-6} J$
Hence D is the correct answer.
answered Jun 20, 2014 by meena.p

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