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Two parallel plate capacitors A and B having capacitance $1 \mu F$ and $5 \mu F$ are charged separately to the same potential of $100\; volt$. Now the positive plate of A is connected to the negative plate of B and negative plate of A to the positive plate of B. Find the final charge on each capacitors and total loss of electrical energy in the given system.

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final total energy $= \large\frac{0.04}{3}$$J$
Loss of energy $=0.03 - \large\frac{0.04}{3} $
$\qquad= \large\frac{5}{3} $$ \times 10^{-2}J$
answered Jun 20, 2014 by meena.p
 

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