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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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Expand each of the expressions:$(102)^5$

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1 Answer

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$(102)^5=(100+2)^5$
$\Rightarrow (100)^5+5C_1(100)^4.2+5C_2(100)^3.2^2+5C_3(100)^2.2^3+5C_4(100)^1.2^4+5C_5(100)^0.2^5$
$\Rightarrow 10,000000000+5\times (100000000)\times 2+\large\frac{5.4}{1.2}$$\times (1000000)\times 4+\large\frac{5.4}{1.2}$$\times (10000)\times 8+\large\frac{5}{1}$$\times 100\times 16+32$
$\Rightarrow 10000000000+1000000000+40000000+8000000+8000+32$
$\Rightarrow 11040808032$
Hence (A) is the correct answer.
answered Jun 20, 2014 by sreemathi.v
 
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