Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Two concentric shells of radii d and 2d respectively are placed far away from a parallel plate capacitor. Each plate of the capacitor is a square of side d and the separation between the plates is $\large\frac{d}{4 \pi}$. The charge on the plates are q and -q. Then the keys $K_1$ and $K_2$ are closed, find the charges on the shells and electric potential energy left in the parallel plate capacitor in equilibrium.

Can you answer this question?

1 Answer

0 votes
Charge on the outer shell $= (q- q_1)$
$\qquad= \large\frac{2}{3}$$q$
Charge on the inner shell $= \large\frac{-2q}{3}$
Energy left in the parallel plate capacitor
$\qquad= \large\frac{1}{2}\frac{q_1^2}{C}$
$\qquad= \large\frac{q^2}{72 \pi \in_0 d}$
answered Jun 21, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App