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# Figure shows a parallel-plate capacitor with plates of width b and length l. The separation between the plates is d. the plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. calculate the energy of the system when a length x of the slab is introduced into the capacitor.

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$\large\frac{\in _0 b V^2}{2d}$$[l+ x(K-1)]$
answered Jun 21, 2014 by