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The plates of a parallel plate capacitor have an area of $90\;cm$ each and are separated by $2.5\;mm$. The capacitor is charged by connecting it to a $400\; V$ supply.View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.

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$U= \large\frac{1}{2} \in_0 E^2$
Hence D is the correct answer.
answered Jun 21, 2014 by meena.p
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