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A $800 pF$ capacitor is charged by a $100\; V$ battery. How much energy is stored by the capacitor? The capacitor is disconnected from the battery and connected to another $800\; pF$ capacitor. What is the electrostatic energy of the system?

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$\large\frac{1}{2} \frac{C_1^2V_1^2}{C_1+C_2}$
Hence C is the correct answer.
answered Jun 22, 2014 by meena.p
 

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