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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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Write the general term in the expansion of $(x^2-y)^6$

$\begin{array}{1 1}(A)\;(-1)^r\large\frac{6!}{r!(6-r)!}\normalsize x^{12-2r}y^r\\(B)\;\large\frac{6!}{r!(6-r)!}\\(C)\;\large\frac{6!}{r!(6-r)!}\normalsize x^{12-2r}y^r\\(D)\;\text{None of these}\end{array} $

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1 Answer

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  • $T_{r+1}=$general term =$nC_ra^{n-r}b^r$
General term=$T_{r+1}=6C_r(x^2)^{6-r}(-y)^r$
$\Rightarrow (-1)^r\large\frac{6!}{r!(6-r)!}$$ x^{12-2r}y^r$
Hence (A) is the correct answer.
answered Jun 23, 2014 by sreemathi.v
 
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