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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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Find the coefficient of $x^5$ in the expansion of the product $(1+2x)^6(1-x)^7$

$\begin{array}{1 1}(A)\;181\\(B)\;161\\(C)\;151\\(D)\;171\end{array} $

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1 Answer

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  • $(a+b)^n=nC_0a^n+nC_1a^{n-1}b+nC_2a^{n-2}b^2+.........nC_ra^{n-r}b^r+......nC_nb^n$
$\Rightarrow 1+12x+60x^2+20\times 8x^3+15\times 16x^4+6\times 32x^6+64x^5$
$\Rightarrow 1+12x+60x^2+160x^3+240x^4+192x^5+64x^6$-----(1)
$\Rightarrow 1-7x+21x^2-35x^3+35x^4-21x^5+7x^6-x^7$-------(2)
Multiplying (1) and (2) and collecting the coefficient of $x^5$
$\therefore$ Coefficient of $x^5$ in the product $(1+2x)^6(1-x)^7$
$\Rightarrow 1\times (-21)+12\times 35+60\times (-35)+160\times 21+240\times (-7)+192\times 1$
$\Rightarrow -21+420-2100+3360-1680+192$
$\Rightarrow 171$
Hence (D) is the correct answer.
answered Jun 23, 2014 by sreemathi.v

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