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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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Given the integers $r > 1,n > 2$ and coefficients of $(3r)^{th}$ and $(r+2)^{nd}$ terms in the binomial expansion of $(1+x)^{2n}$ are equal then

$\begin{array}{1 1}(A)\;n=2r\\(B)\;n=3r\\(C)\;n=2r+1\\(D)\;\text{None of these}\end{array} $

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1 Answer

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  • $T_{r+1}=nC_r a^{n-r}b^r$
$\therefore 2nC_{r+1}=2nC_{3r-1}$
$\Rightarrow r+1=3r-1$
$\Rightarrow (r+1)+(3r-1)=2n$
$\Rightarrow 4r=2n$ or $r=\large\frac{n}{2}$
$\Rightarrow r=\large\frac{n}{2}$
$\Rightarrow n=2r$
Hence (A) is the correct answer.
answered Jun 24, 2014 by sreemathi.v

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