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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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If the coefficient of $2^{nd},3^{rd}$ and $4^{th}$ terms in the expansion of $(1+x)^n$ are in $A.P$ then the value of $n$ is

$\begin{array}{1 1}(A)\;2\\(B)\;7\\(C)\;11\\(D)\;14\end{array} $

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  • $T_{r+1}=nC_ra^{n-r}b^r$
Given :
$nC_1,nC_2,nC_3$ are in A.P
$\Rightarrow 2nC_2=nC_1+nC_3$
$\Rightarrow \large\frac{2n(n-1)}{1.2}=\frac{n}{1}+\frac{n(n-1)(n-2)}{1.2.3}$
$\Rightarrow 6n(n-1)=6n+n(n-1)(n-2)$
$\Rightarrow n^3-9n^2+14n=0$
$\Rightarrow n(n^2-9n+14)=0$
$\Rightarrow n=0$
$n-2=0$ or $n-7=0$
$\therefore n=7$(There are atleast 4 terms in $(1+x)^n$)
Hence (B) is the correct answer.
answered Jun 25, 2014 by sreemathi.v

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