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Two identical capacitors have the same capacitance C. One of them is charged to potential $V_1$ and the other to $V_2$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is

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$(C) \large\frac{1}{4} $$C (V_1 -V_2)^2$
answered Jun 25, 2014 by meena.p

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