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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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The middle term in the expansion of $\big(x+\large\frac{1}{x}\big)^{10}$ is

$\begin{array}{1 1}(A)\;10C_1\large\frac{1}{x}\\(B)\;10C_5\\(C)\;10C_6\\(D)\;10C_7x\end{array} $

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1 Answer

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  • When n is even,middle term=$(\large\frac{n}{2}$$+1)^{th}$ term
Middle term =$\large\frac{n}{2}$$+1$
$\Rightarrow \large\frac{10}{2}$$+1=6^{th}$
$T_{5+1}=10C_5 x^{10-5} (\large\frac{1}{x})^5$
$\Rightarrow 10C_5 x^5.\large\frac{1}{x^5}$
$\Rightarrow 10C_5 $
Hence (B) is the correct answer.
answered Jun 25, 2014 by sreemathi.v
 

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