Obvious that the relation R is “x is the square of y”.

set-builder form, R = {(x, y): x is the square of y, x $ \in $ P, y $ \in $ Q}

roster form, R = {(9, 3), (9, –3), (4, 2), (4, –2), (25, 5), (25, –5)}

domain of this relation is {4, 9, 25}.

range of this relation is {– 2, 2, –3, 3, –5, 5}.

that the element 1 is not related to any element in set P.

The set Q is the codomain of this relation.