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Home  >>  CBSE XI  >>  Math  >>  Binomial Theorem

The $10^{th}$ term in the expansion of $(x-1)^{11}$ (in decreasing power of $x$) is

$\begin{array}{1 1}(A)\;-x\\(B)\;-11x\\(C)\;-x^2\\(D)\;-11C_2x^2\end{array} $

1 Answer

Toolbox:
  • $T_{r+1}=nC_ra^{n-r} b^r$
$T_{10}=T_{9+1}=11C_9(x)^{11-9}(-1)^9$
$\Rightarrow 11C_9x^2$
$\Rightarrow -11C_2x^2$
Hence (D) is the correct answer.
answered Jun 26, 2014 by sreemathi.v
 

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