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Determine order and degree of $ (y^{'''})^2+(y^{''})^3+(y^{'})^4+y^5=0 $

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  • The highest order derivative present in the differential equation determines its order.
  • The highest power raise to the derivative determines its degree.
$ (y^{'''})^2+(y^{''})^3+(y^{'})^4+y^5=0 $
The order of the given equation is 3.
The degree corresponding to the highest order is 2
answered Sep 27, 2013 by sreemathi.v

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