Given three coins are tossed.

Therefore,the sample space (ie) $2^3=8$ possible outcome

$S=\{HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\}$

Given :

A=Three heads shows ={HHH}

B=Two heads and one tail show ={HHT,HTH,THH}

C=Three tail show ={TTT}

D=A head shows on the first toss={HHH,HHT,HTH,HTT}

Here $A \cap B=\phi$

$A \cap C=\phi$

$A \cap D\neq \phi$

$B \cap C= \phi$

$B \cap D\neq \phi$

$C \cap D= \phi$

$A \cap B \cap C= \phi$

It is clear that A and B ,A and C,B and C,C and D and A,B and C are mutually exclusive.