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If f: R $ \rightarrow $ R is defined by f (x) = x − 2 and g: R $ \rightarrow $ R in the modulus function, then $ \large\frac{f}{g}$$ R - {0} \rightarrow R$ is given by

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\[\bigg(\large\frac{f}{g} \bigg) (x) = \left\{ \begin{array}{l l} 1-\large\frac{2}{x}, & \quad x > 0 \\ \large\frac{2}{x}-1, & \quad \; x < 0 \end{array} \right.\]
Hence (B) is the correct answer.
answered Jun 28, 2014 by thanvigandhi_1
 

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