Step 1:

Let the equation of the plane containing the given point $(1,-1,2)$ is

$A(x-x_1)+B(y-y_1)+C(z-z_1)=0$

(i.e) $A(x-1)+B(y+1)+c(z-2)=0$------(1)

Applying the condition of perpendicularly to the plane in equ(1) with the plane

$2x+3y-2z=5$ and $x+2y-3z=8$

We have $2A+3B-2C=0$ and $A+2B-3C=0$

Step 2:

Let us solve three two equations,we get

$A=-5C$

$B=4C$

The required equation is

$-5C(x-1)+4C(y+1)+c(z-2)=0$

$5x-4y-z-7=0$

$5x-4y-z=7$