Comment
Share
Q)

# A coin is tossed twice,what is the probability that atleast one tail occurs

$\begin{array}{1 1}(A)\;\large\frac{3}{4}\\(B)\;\large\frac{4}{5}\\(C)\;\large\frac{3}{5}\\(D)\;\large\frac{2}{3}\end{array}$

Comment
A)
• Required probability =$\large\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$
The sample space $S=\{HH,HT,TH,TT\}$
$\therefore$ E={HT,TH,TT}
$\therefore$ Required probability =$\large\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$
$\Rightarrow \large\frac{3}{4}$
$\therefore$ The Answer is $\large\frac{3}{4}$