$\begin{array}{1 1}(A)\;\large\frac{2}{3}\\(B)\;\large\frac{1}{2}\\(C)\;\large\frac{1}{5}\\(D)\;\text{None of these}\end{array} $

- The formula used to calculate is Probability $P=\large\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$

Step 1:

Given a die is thrown

$\therefore$ The sample space S={1,2,3,4,5,6}

Let E be the event greater than equal to 3 will appear.

$\therefore$ E={3,4,5,6}

Step 2:

Probability =$\large\frac{n(E)}{n(S)}$

$\Rightarrow \large\frac{4}{6}$

$\Rightarrow \large\frac{2}{3}$

Hence (A) is the correct answer.

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