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A die is thrown,find the probability of following event : A number less than 6 will appear

$\begin{array}{1 1}(A)\;\large\frac{1}{6}\\(B)\;\large\frac{5}{6}\\(C)\;\large\frac{3}{5}\\(D)\;\large\frac{1}{2}\end{array} $

1 Answer

  • The formula used to calculate is Probability $P=\large\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{n(E)}{n(S)}$
Step 1:
Given a die is thrown
$\therefore$ The sample space S={1,2,3,4,5,6}
Let E be the event the number less than 6 will appear.
Probability =$\large\frac{n(E)}{n(S)}$
$\Rightarrow \large\frac{5}{6}$
Hence (B) is the correct answer.
answered Jun 30, 2014 by sreemathi.v