$\begin{array}{1 1}(A)\;\large\frac{1}{52}\\(B)\;\large\frac{3}{52}\\(C)\;\large\frac{5}{52}\\(D)\;\text{None of these}\end{array} $

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- The formula used to solve this problem
- Probability $P=\large\frac{n(E)}{n(S)}$

Card is an ace of spades

Let E be the event that "an ace of spade"

$\therefore n(E)=1$

Step 2:

$\therefore$ Probability of event getting an ace of spade =$\large\frac{n(E)}{n(S)}$

$\Rightarrow \large\frac{1}{52}$

Hence (A) is the correct answer.

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