$\begin{array}{1 1}(A)\;\large\frac{1}{13}\\(B)\;\large\frac{2}{13}\\(C)\;\large\frac{3}{13}\\(D)\;\text{None of these}\end{array} $

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- The formula used to solve this problem, Probability $P=\large\frac{n(E)}{n(S)}$

Probability the card is an ace

In a pack of 52 cards,there are 4 aces

$\therefore n(E)=4$

Probability of event getting an ace $P=\large\frac{n(E)}{n(S)}$

$\Rightarrow \large\frac{4}{52}$

$\Rightarrow \large\frac{1}{13}$

Hence (A) is the correct answer.

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