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A card is selected from a pack of 52 cards.Calculate the probability the card is an ace

$\begin{array}{1 1}(A)\;\large\frac{1}{13}\\(B)\;\large\frac{2}{13}\\(C)\;\large\frac{3}{13}\\(D)\;\text{None of these}\end{array}$

Toolbox:
• The formula used to solve this problem, Probability $P=\large\frac{n(E)}{n(S)}$
Probability the card is an ace
In a pack of 52 cards,there are 4 aces
$\therefore n(E)=4$
Probability of event getting an ace $P=\large\frac{n(E)}{n(S)}$
$\Rightarrow \large\frac{4}{52}$
$\Rightarrow \large\frac{1}{13}$
Hence (A) is the correct answer.