$\begin{array}{1 1}(A)\;\large\frac{1}{2}\\(B)\;\large\frac{1}{4}\\(C)\;\large\frac{1}{5}\\(D)\;\text{None of these}\end{array} $

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- Probability $P=\large\frac{n(E)}{n(S)}$

Step 1:

Probability the card is a black card

In a pack of 52 cards,there are 26 black cards

$\therefore n(E) =26$

Step 2:

Probability of the event getting a black card =$\large\frac{n(E)}{n(S)}$

$\Rightarrow \large\frac{26}{52}$

$\Rightarrow \large\frac{1}{2}$

Hence (A) is the correct answer.

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