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There are four men and six women on the city council.If one council member is selected for a committee at random,how likely is it that it is a woman ?

$\begin{array}{1 1}(A)\;\large\frac{3}{5}\\(B)\;\large\frac{2}{5}\\(C)\;\large\frac{4}{5}\\(D)\;\text{None of these}\end{array} $

1 Answer

  • Probability =$\large\frac{n(E)}{n(S)}$
Step 1:
Given : 4 men and 6 women are in the city council.
Number of sample space $n(S)=10$
Step 2:
Let E be the event that a women is selected
$\therefore n(E)=6$
Step 3:
Probability =$\large\frac{n(E)}{n(S)}$
$\Rightarrow \large\frac{6}{10}$
$\Rightarrow \large\frac{3}{5}$
Hence (A) is the correct answer.
answered Jun 30, 2014 by sreemathi.v

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