$\begin {array} {1 1} (A)\;x-y-1=0 & \quad (B)\;x+y-1=0 \\ (C)\;x+y-1=0 & \quad (D)\;y-x=1 \end {array}$

- Equation of a line which has $a$ and $b$ as the $x$ and $y$ intercepts is $ \large\frac{x}{a}$$+\large\frac{y}{b}$$=1$

Step 1

It is given that the straight line cuts of equal intercepts.

$ \therefore \large\frac{x}{a}$$+\large\frac{y}{b}$$=1$

$ \Rightarrow x+y=a$

It is also given that the line passes through the point (1, -2)

$ \therefore 1+(-2)=a$

$ \Rightarrow a = -1$

Hence the eqution of the line is

$x+y=-1$ or

$x+y+1=0$

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